Two Thousand Nine Hundred Thirty Five Subtract One Thousand Eight Hundred 43

Studentka2010 [4]

First, find the area of the larger sector (the 360-130=230 degree sector), then add the area of the triangle.
area of the larger sector:(230/360)π*11.1²≈247.17
area of the triangle when two sides and the angle between the two sides are given: (absinФ)/2. In this case, a=11.1, b=11.1, Ф=130
(11.1*11.1*sin130)/2≈47.19
the total area is 247.17+47.19≈294.4
Please use your calculator to double check my numbers.

4 0

4 years ago

a father and son are digging a garden that is 7 feet wide. the father, working alone, can dig the garden in 3 hours. The son can

Anna71 [15]

There is a formula for this. (see attached)

Time = 3 * 4 / (3+4)
Time = 12 / 7
Time = <span> 1.714286 </span>
Time = <span> 1.7 (rounded)

</span>

3 0

3 years ago

What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in

vovangra [49]

<h3>Given :</h3>

Distance = 175
Time 1 = 4 hours

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Different between two speeds when distance is same.

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<h3>Solution:</h3>

In first part we will find speed 1 in which time is 4 hours

we know:-

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

So:-

$\dashrightarrow\sf speed_1 = \dfrac{distance}{time_1}$

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$\dashrightarrow\sf speed_1 = \dfrac{175}{4}$

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$\dashrightarrow\bf speed_1 = 43.75 \: km {h}^{ - 1}$

In first part we will find speed 2 in which time is 3 hours

Again:

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

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$\dashrightarrow\sf speed_2 = \dfrac{distance}{time_2}$

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$\dashrightarrow\sf speed_2 = \dfrac{175}{3}$

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$\dashrightarrow\bf speed_2 = 58.33kmh^{-1}$

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In this part we will find different between speed 1 and speed 2

$\bigstar \boxed{\rm Difference = speed_2 - speed_1}$

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So :

$\dashrightarrow\sf Difference = speed_2 - speed_1 \\$

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$\dashrightarrow\sf Difference =58.33 - 43.75\\$

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$\dashrightarrow\bf Difference =14.58kmh^{-1}\\$

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$\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}$

4 0

3 years ago

The germination rate is the rate at which plants begin to grow after the seed is planted.

chubhunter [2.5K]

Answer:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

$\hat p=\frac{7}{15}=0.467$ estimated proportion of seeds germinated

$p_o=0.9$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:

Null hypothesis: $p\geq 0.9$

Alternative hypothesis: $p < 0.9$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

4 0

3 years ago

Which property justifies rewriting 3x - 5x as (3 - 5)x ?

slavikrds [6]

A) distributive property

5 0

3 years ago