Question

A park ranger wants to shoot a monkey hanging from a branch of a tree with a tranquilizing dart. The ranger aims directly at the monkey, not realizing that the dart will follow a parabolic path and thus will fall below the monkey. The monkey, however, sees the dart leave the gun and lets go of the branch to avoid being hit. Will the monkey be hit anyway? Does the velocity of the dart affect your answer, assuming that it is great enough to travel the horizontal distance to the tree before hitting the ground? Defend your answer.

Answer 1

Answer:

Yes it will hit the monkey

Explanation:

Here when park ranger aim the position of monkey and then shoot towards it then in this position the velocity of the dart has two components

$v_x = vcos\theta$

$v_y = vsin\theta$

Now when the dart reached the same horizontal distance as that the position of monkey then time taken by it

$t = \frac{x}{v cos\theta}$

now in the same time the height of the dart is given as

$y = (vsin\theta) t - \frac{1}{2}gt^2$

$y = (vsin\theta)(\frac{x}{vcos\theta}) - \frac{1}{2}g(\frac{x}{vcos\theta})^2$

$y = x tan\theta - \frac{1}{2}gt^2$

here let say monkey is at height H initially then

$H = x tan\theta$

$y = H - \frac{1}{2}gt^2$

this above equation also shows the position of monkey after t time of drop

so here dart will hit the monkey

Answer 2

Answer:

(a gas) (b solid )(c liquid )

Explanation:

Because i took the test your welcome :)))