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drek231 [11]
3 years ago
9

astronaut is traveling in a space vehicle moving at 0.510c relative to the Earth. The astronaut measures her pulse rate at 61.0

beats per minute. Signals generated by the astronaut's pulse are radioed to the Earth when the vehicle is moving in a direction perpendicular to the line that connects the vehicle with an observer on the Earth. (Due to vehicle's path there will be no Doppler shift in the signal.) What pulse rate does the Earth-based observer measure?
Physics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

45.13 beats/min

Explanation:

Speed of space vehicle  = 0.51c

the pulse rate measured by the astronaut= 61.0 beats per minute

Pulse rate measured by the Earth observer is given by

=(pulse\ rate)\sqrt{1-\frac{v^2}{c^2} }

putting vales we get

=61\sqrt{1-\frac{0.51^2c^2}{c^2} }

= 45.13 beats/min

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Answer:

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Explanation:

According to the formula v = f¶

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f is the frequency

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According to the question, if the wavelength is doubled, the velocity (v) will also double while the frequency (f) remains unchanged.

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What is a safe following distance between your automobile and the vehicle in front of you?
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Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.37 times a second. A tack is stuck in the tire a
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Answer:

The tangential speed of the tack is 8.19 m/s.

Explanation:

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\omega =3.37rev/s \times(\frac{2\pi rad}{1s} )\\\\=21.174rad/s

Use the relation of angular speed with tangential speed to find the tangential speed of the tack.

The tangential speed v of the tack is given by following expression

v = ω r

Here, r is the distance to the tack from axis of rotation.

Substitute 21.174 rad/s for ω, and 0.387 m for r in the above equation to solve for v.

v = 21.174 × 0.387

v = 8.19m/s

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2 years ago
A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformati
Slav-nsk [51]

The question is incomplete. The complete question is :

A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformation cycle. At a time, t = 0, a tensile stress of 20 MPa is applied instantaneously and maintained for 100 s. The stress is then removed at a rate of 0.2 MPa s−1 until the polymer is unloaded. If the creep compliance of the material is given by:

J(t) = Jo (1 - exp (-t/to))

Where,

Jo= 3m^2/ GPA

to= 200s

Determine

a) the strain after 100's (before stress is reversed)

b) the residual strain when stress falls to zero.

Answer:

a)-60GPA

b) 0

Explanation:

Given t= 0,

σ = 20Mpa

Change in σ= 0.2Mpas^-1

For creep compliance material,

J(t) = Jo (1 - exp (-t/to))

J(t) = 3 (1 - exp (-0/100))= 3m^2/Gpa

a) t= 100s

E(t)= ΔσJ (t - Jo)

= 0.2 × 3 ( 100 - 200 )

= 0.6 (-100)

= - 60 GPA

Residual strain, σ= 0

E(t)= Jσ (Jo) ∫t (t - Jo) dt

3 × 0 × 200 ∫t (t - Jo) dt

E(t) = 0

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