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Andreyy89
3 years ago
13

A helicopter is moving at a horizontal speed when it drops a container so it lands with a range of 80 meters. If the helicopter

is 37 meters from the ground what is its horizontal speed? (10 points)
Physics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

The horizontal speed is approximately 29 m/s.

Explanation:

Given that; range = 80 meters, height = 37 meters.

The horizontal speed can be determined by:

R = U\sqrt{\frac{2H}{g} }

Where R is the range, U is the velocity of the object, H is the height and g is the acceleration due to gravity (9.8 m/s^{2}).

So that:

80 = U\sqrt{\frac{2*37}{9.8} }

     = U\sqrt{\frac{74}{9.8} }

     = U\sqrt{7.55102}

80 = 2.747912U

⇒ U = \frac{80}{2.747912}

       = 29.1130

U ≅ 29 m/s

The horizontal speed is approximately 29 m/s.

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A stone is thrown vertically upward with a speed of 15.0 m/s from the edge of a cliff 75.0 m high.How much later does it reach t
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5.72 seconds

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v=u+at\\\Rightarrow 0=15-9.81\times t\\\Rightarrow \frac{-15}{-9.81}=t\\\Rightarrow t=1.52 \s

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s=ut+\frac{1}{2}at^2\\\Rightarrow s=15\times 1.52+\frac{1}{2}\times -9.81\times 1.52^2\\\Rightarrow s=11.47\ m

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s=ut+\frac{1}{2}at^2\\\Rightarrow 86.47=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{86.47\times 2}{9.81}}\\\Rightarrow t=4.2\ s

Time taken by the stone to travel 86.47 m to the water is is 4.2 seconds

The stone reaches the water after 4.2+1.52 = 5.72 seconds after throwing the stone

v=u+at\\\Rightarrow v=0+9.81\times 86.47 = 848.27\ m/s

Speed just before hitting the water is 848.27 m/s

3 0
3 years ago
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