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Scilla [17]
3 years ago
7

Someone please help me with this one :)

Chemistry
1 answer:
Crazy boy [7]3 years ago
4 0
I think it is the answer choice B
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The cell notation is Pb_{(s)}  Pb^{2+} _{(aq)} ║Cu^{+2}_{aq}  Cu_{(s)} and the cell potential is 0.464

The reaction occurred while losing of hydron is known as oxidation reaction

We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.

The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction

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Calculating the Cell potential

E°cell  = E°(reduction) - E°(oxidation)

           = 0.34 - (-0.0124)

           = 0.464

Hence the cell potential is 0.464

Learn more about Cell potential here

brainly.com/question/11638563

#SPJ10

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