<h3>
Answer:</h3>
28.17 %
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Explanation:</h3>
In the question we are required to determine the percent by mass of nitrogen in (NH₄)₃PO₄.
- To calculate the percent by mass of an element in a compound we use the formula;
- % by mass =(Mass of the element÷ Relative formula mass of the compound)100
In this case;
- Atomic mass of nitrogen is 14.0 g/mol
But; There are three nitrogen atoms in (NH₄)₃PO₄.
Therefore; Mass of nitrogen in (NH₄)₃PO₄ = 14.0 × 3
= 42 g
The relative formula mass of (NH₄)₃PO₄ = 149.0867 g/mol
Thus;
% by mass of N = (42 g ÷ 149.0867 g/mo)× 100%
= 28.17 %
Therefore, the % by mass of N is (NH₄)₃PO₄ is 28.17%
Answer:
Electron pair geometry- tetrahedral
Molecular geometry- Trigonal Pyramidal
Explanation:
PCl3 has four electron domains on the outermost shell of the central atom in the molecule. This implies that it has a tetrahedral electron pair geometry according to Valence Shell Electron Pair Repulsion theory.
These four electron pairs are composed of three bond pairs and one lone pair. The presence of a lone pair of electrons leads to a trigonal pyramidal molecular geometry due to electron pair repulsions.
it means that it takes 4,200 joules of energy (that's the j) to raise the temperature of 1 kg of water (kg-1)
Answer:
14.9 g is the ideal yield of Cu(NO₃)₂
Explanation:
Reactants for the reaction: Cu and AgNO₃
Products: Copper nitrate and Ag
The balanced reaction is: Cu(s) + 2AgNO₃(aq) → 2Ag (s) + Cu(NO₃)₂
As the silver nitrate is in excess, the Cu will be the limiting reagent.
We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles
Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.
0.0794 mol . 187.55 g /1 mol = of Cu(NO₃)₂
Yes a recessive allele can hide their trait if a dominant allele is present.
