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velikii [3]
3 years ago
10

A sheet of aluminum foil weighs 2.07g. If the sheet is 24cm long and 20cm wide, how thick is the sheet in micrometers? The densi

ty of aluminum is 2.7 g/cm3.
Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

h=1.60\mu m

Explanation:

Hello,

In this case, given the density and the mass of the aluminum foil, we can compute the occupied volume as shown below:

\rho =\frac{m}{V}\\ \\V=\frac{m}{\rho}=\frac{2.07g}{2.7g/cm^3}  =0.767cm^3

Next, since the volume is defined as:

V=24cm*20cm*h

Whereas h accounts for its thickness, we can find it to be:

h=\frac{V}{24cm*20cm}=\frac{0.767cm^3}{20cm*24cm}\\  \\h=1.60x10^{-3}cm*\frac{10000\mu m}{1cm} \\\\h=1.60\mu m

Regards.

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2 years ago
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Electrons in an atom can be classified as core electrons and valence electrons. Valence electrons are those electrons which are present in valence shell and participates in bond formation. While, Core electrons are all remaining electrons which are not present in valence shell, hence not take part in bonding.

Atomic number of Selenium (Se) is 34 hence it has 34 electrons with following electronic configuration;

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From electronic configuration it is found that the valence shell is 4, and the number of electrons present in valence shell are 6. So, 

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             Core Electrons  =  28

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