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3 years ago

10

write a good scientific question that can be answered by Guadalupe based on what is described above. Label the independent and d

ependent variable within your question.

1 answer:

kakasveta [241]3 years ago

4 0

To do that, we would need to know what is "described above".

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What gravitational force does the moon produce

dangina [55]

Answer:

$F = 1.94 \times 10^{20} N$

Explanation:

Mass of earth ; $M = 5.973 \times 10^{24} kg$

Mass of moon ; $m = 7.34 \times 10^{22}kg$

distance between them is ; $d = 3.88 \times 10^{8}m$

Gravitational constant is given by

$G = 6.67 \times 10^{-11} m^{3}kg^{-1}s^{-2}$

So , the gravitational force between them is

$F = \frac{GMm}{d^{2}}$

Insert the values

$F = \frac{6.67 \times 10^{-11} \times 5.973 \times 10^{24} \times 7.34 \times 10^{22}}{(3.88 \times 10^{8})^{2}} N$

So,

$F = 1.94 \times 10^{20} N$

Thus , the force between earth and moon is $F = 1.94 \times 10^{20} N$

6 0

3 years ago

All objects in the universe are attracted to each other by the force of. A. effort

stepladder [879]

Answer:

It encapsulates the idea that all the particles of matter in the universe attract each other through the force of gravity – Newton's law tells us how strong that attraction is. ...

Explanation:

your answer

4 0

3 years ago

Read 2 more answers

If you walk 1.4 km north and then 4.8 km east, what are the magnitude and direction of your resultant displacement?

olchik [2.2K]

A

North and east are perpendicular directions hence we can use them as the basis of our coordinate system. The coordinates of this point can then simply be represented as

P = 1.4 N + 4.8 E (km)

The magnitude can be given by the right triangle formula :

P = $\sqrt{N^2 + E^2}$

= 5 km

Direction = atan(N/E) = 16.3 deg north of east = 73.7 deg east of north

8 0

3 years ago

Carbon dioxide in a piston-‐‐cylinder is expanded in a polytropic manner. The initialtemperature and pressure are 400 K and 550

Arisa [49]

Answer:

q_poly = 14.55 KJ/kg

Explanation:

Given:

Initial State:

P_i = 550 KPa

T_i = 400 K

Final State:

T_f = 350 K

Constants:

R = 0.189 KJ/kgK

k = 1.289 = c_p / c_v

n = 1.2 (poly-tropic index)

Find:

Determine the heat transfer per kg in the process.

Solution:

-The heat transfer per kg of poly-tropic process is given by the expression:

q_poly = w_poly*(k - n)/(k-1)

- Evaluate w_poly:

w_poly = R*(T_f - T_i)/(1-n)

w_poly = 0.189*(350 - 400)/(1-1.2)

w_poly = 47.25 KJ/kg

-Hence,

q_poly = 47.25*(1.289 - 1.2)/(1.289-1)

q_poly = 14.55 KJ/kg

4 0

3 years ago

2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure

egoroff_w [7]

We have,

The mass of sally's mug is 1 kg
The pressure appliedby the mug is 1100 pascal.

We know that,

Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

F = ma
F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
F = 10 N

Just put all the values in the formula now;

P = F/A
1100 = 10 / A
1100/10 = A
110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

Surface area = Circumference

So, let's solve it;

Circumference = 2πr
110 = 2 × 22/7 × r
110 × 7/2 × 22 = r
5 × 7 = r
35 cm = r

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7 0

3 years ago