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Eva8 [605]
3 years ago
11

A box is on a ramp that is at angle θ to the horizontal. As θ is increased from zero, and before the box slips, do the following

increase, decrease, or remain the same: (a) the component of the gravitational force on the box, along the ramp, (b) the magnitude of the static frictional force on the box from the ramp, (c) the component of the gravitational force on the box, perpendicular to the ramp, (d) the magnitude of the normal force on the box from the ramp, and (e) the maximum value fs,max of the static frictional force
Physics
1 answer:
KIM [24]3 years ago
4 0
The correct answer for the question that is being presented above is this one: "(d) the magnitude of the normal force on the box from the ramp." A box is on a ramp that is at angle θ to the horizontal. As θ is increased from zero, and before the box slips, do the following increase, decrease, or remain the same and  <span> the magnitude of the normal force on the box from the ramp.</span>
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The discovery of which force most directly impacted our society by allowing the development of nuclear weapons
zhuklara [117]

nuclear ... truman, hiroshima, nagasaki

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3 years ago
A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p
timama [110]

Answer: 0.1851 \frac{kg}{m^{3}}

Explanation:

We have this concentration in units of mg/ml:

\frac{45 mg}{243 ml}

And we need to express it in kg/m^{3}, knowing:

1 ml= 1 cm^{3}

1 m^{3}= (100 cm) ^{3}

1g = 1000 mg

1 kg = 1000 g

Hence:

\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}

5 0
3 years ago
The weight of a block on the inclined plane is 500 N and the angle of incline is 30 degrees. What is the magnitude of the force
yanalaym [24]

Answer:

250 N

433 N

Explanation:

N = Normal force by the surface of the inclined plane

W = Weight of the block = 500 N

f = static frictional force acting on the block

Parallel to incline, force equation is given as

f = W Sin30

f = (500) Sin30

f = 250 N

Perpendicular to incline force equation is given  

N = W Cos30

N = (500) Cos30

N = 433 N

3 0
3 years ago
An engineering intern is studying the effect of temperature on the resistance of a current carrying wire. She applies a voltage
Mars2501 [29]

Answer:

I=2.80 A

Explanation:

We Know that    R =R₀(1+∝ ΔT)

                           R=R₀ (1+3.9*10⁻³ *(61-20))

                           R=R₀ (1.1599)

                           I=V/R=V/(R₀ (1.1599)

                           1.4 = V/(R₀ (1.1599)                       ∵ equation 1

                     We have to calculate I when T=-88°

                              R =R₀(1+∝ ΔT)

                             R=R₀ (1+3.9*10⁻³ *(-88-20))

                             R=R₀ (0.5788)

                             I=V/(R₀ (0.5788)                          ∵equation 2

Dividing equation 2 by equation 1

                             \frac{I}{1.4} =\frac{1.1599}{0.5788}

                            I = 2.80 A

                         

4 0
3 years ago
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Como estan formados los musculos?
VikaD [51]

Answer:

Explanation: El músculo esquelético está formado por fibras musculares, rodeadas de una capa de tejido conjuntivo, denominada endomisio. Las fibras se reúnen en fascículos primarios, que también están rodeados por otra capa de tejido conjuntivo, esta vez, más grueso, denominada perimisio.

3 0
3 years ago
Read 2 more answers
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