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Sladkaya [172]
3 years ago
12

there is only one basic format for a professional report. a. audience b. All of these should be considered when deciding on a re

port format c. length d.purpose
Physics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

The answer is letter b. All of these should be considered when deciding on a report format.

Explanation:

A Professional Report is a type of formal document about a topic or information that is intended for a specific audience or purpose. The report's style of writing needs a lot of knowledge from the writer. Oftentimes, it involves the following important elements: <em>Title, Summary, Body, Discussion, Conclusion and Recommendation. </em>

The writer should write according to his target audience and purpose. He also needs to consider the length of his report, as well as the suitable words and sentences that he should use.

Thus, all of the choices are important in writing a professional report. So, the answer is letter b.

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A 65 kg box is lifted by a person pulling a rope a distance of 15 meters straight up at a constant speed. How much Power is requ
Y_Kistochka [10]

Answer:

Power is 1061.67W

Explanation:

Power=force×distance/time

Power=65×9.8×15/9 assuming gravity=9.8m/s²

Power=3185/3=1061.67W

8 0
3 years ago
Alice kicks a 0. 25 kg soccer ball with 0. 5 N of force. What force does the ball exert on Alice’s foot as she kicks it? N.
leva [86]

The force exerted on Alice’s foot as she kicks the ball is 1.25 N.Force can be defined as the influence that can accelerate the object.

<h3>What is force?</h3>

Force can be defined as the influence that can accelerate the object. From Newton's Second Law of motion,

F = ma

Where,

F - force

m - mass = 0. 25 kg

a - acceleration = 5 N

Put the values in the formula,

F = 0.25 \times 5\\\\F = 1.25 \rm \ N

Therefore, the force exerted on Alice’s foot as she kicks the ball is 1.25 N.

Learn more about Force:

brainly.com/question/2840101

3 0
3 years ago
A pendulum is swinging back and forth with no non-conservative forces acting on it. At the highest points of its trajectory, the
Setler [38]

Answer:

b. K = U

Explanation:

In this case you have that there are no non-conservative forces over the pendulum. Hence, the total mechanical energy if the pendulum must conserve. You take into account that the potential and kinetic energy of a pendulum are given by:

E_T=K+U=\frac{1}{2}mv^2+mgh

m: mass of the pendulum

h: height of the pendulum

v: speed

In each moment of the trajectory of the pendulum ET does not change.

You have that, at the lowest point U=0J  and for the highest point K=0J. For that point K=ET and U=ET respectively.

Hence, for a mid-way between those points it is necessary that:

b. K = U

7 0
3 years ago
What is Stefan Boltzmann's law???<br> Need explaination
sukhopar [10]

Answer:

The Stefan–Boltzmann law, also known as Stefan's law, states that the total energy radiated per unit surface area of a black body in unit time (known variously as the black-body irradiance, energy flux density, radiant flux, or the emissive power), j*, is directly proportional to the fourth power of the black body's

Explanation:

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7 0
3 years ago
Read 2 more answers
AP Physics I, shouldn't be too hard.
Nana76 [90]

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision =  9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

5 0
3 years ago
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