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loris [4]
4 years ago
5

Calculate the mole fraction of benzene in a mixture that contains 45.2 g of benzene and 115.8 g of toluene.

Chemistry
1 answer:
ololo11 [35]4 years ago
6 0

molecular weight of toluene = 92 g/mol  

C6 = 12 x 6 = 72  

H5 = 1 x 5 =5  

CH3 = 12 + 1 x 3 =15  

molecular weight of benzene = 78 g/mol  

C6 = 12 x 6 = 72  

H6 = 1 x 6 = 6  

moles toluene:  

115.8 / (92 g/mol) = 1.25 mol  

moles benzene:  

45.2/ (78 g/mol) = 0.57mol  

total moles: 1.25  + 0.57= 1.82 moles  

mole fraction of toluene:  

1.25 mol  / 1.82 moles  = 0.68



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Answer:

The answer to your question is 34 g of H₂O₂    

Explanation:

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Process

1.- Write the balanced chemical reaction

                   H₂O₂  ⇒   H₂  +  O₂

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3.- Use proportions to calculate the mass of O₂

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                     x                   -------------- 32g of O₂

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Anuta_ua [19.1K]

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Answer:

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