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Anuta_ua [19.1K]

3 years ago

7

Help me people who know Trigonometry only! calculate the length a to two decimal places.

2 answers:

aleksandr82 [10.1K]3 years ago

6 0

B or c that's some help.

horrorfan [7]3 years ago

5 0

I think is c don’t you

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Find the lowest common denominator 3x^3y^2 and 18xy^3

Katyanochek1 [597]

$3x^3y^2=(3)(x)(x)(x)(y)(y)\\\\18xy^3=(3)(3)(2)(x)(y)(y)(y)\\\\Answer:(3)(3)(2)(x)(x)(x)(y)(y)(y)=18x^3y^3$

7 0

3 years ago

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

A rectangular garden 6 meters wide has a diagonal measuring 10 meters. find the perimeter of the garden.

FromTheMoon [43]

The perimeter would be:
6+6+10+10
12+20
perimeter= 32
HOPE THIS HELPS YOU! ^_^

7 0

3 years ago

Help! Help! Help! Help!

alexgriva [62]

A. C(n)=10n+125

cost×number of buttons is equal to 10 cents times the number of buttons, plus the $125 cost of the button machine

6 0

3 years ago

Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0

Artyom0805 [142]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

$x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-52}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{-36}}{2}$

Next, factor out i (i = √-1):

$x=\frac{4\pm \sqrt{36}i}{2}$

Next, solve the square root:

$x=\frac{4\pm 6i}{2}$

Lastly, divide and <u>your answer is:</u>

$x=2\pm 3i$

5 0

3 years ago

Read 2 more answers