The deer eats grass, the percentage of energy will the deer acquire from the grass will be dependent on the food chain then the accurate solution is 10 percent.
- In a food chain, the simplest 10 percent of the strength is transferred from one trophic stage to another.
- The grass is the manufacturer and the deer is the number one consumer, so, whilst the deer eats the grass, it acquires 10 percent of the entire strength of the grass. Rest strength is dissipated withinside the surroundings thru the metabolic tactics taking location withinside the grass.
<h3>What is the position of deer in the food chain?</h3>
The 2nd trophic stage includes organisms that consume the producers. These are known as number one purchasers or herbivores. Deer, turtles, and plenty of varieties of birds are herbivores. Secondary purchasers consume the herbivore.
Thus it is clear that 10 percent of energy will the deer acquire from the grass.
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<u>Answer</u>:
1.a) Species. It is the lowest taxon and represents the scientific name of the organism.
b) The species name is part of the binomial system of nomenclature developed by Linnaeus.
Thus it is composed of two parts each with its own writing rules (ex. gray wolf - <em>Canis lupus</em>):
A. the genus or generic name
- written first
- always underlined or italicized
- the first letter is always capitalized
ex. <em>Canis</em>
B. the specific epithet or species name
- is written second
- always underlined or italicized
- never capitalized
ex. <em>lupus</em>
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2. The results should always be the same. A dichotomous key is an identification tool based on a series of choices between alternative characters (dichotomous = divided into two parts). Thus, there is no room for subjective observation that may lead to another result. If the morphological traits of the organism are correctly identified, the the result should always be the same. Any differences occur due to errors on the scientist's part.
Answer: alpha
Explanation: Alpha particles are fast moving streams of positively charged particles that are shown to be Helium nuclei. They have a mass
number of 4 and an atomic number of 2 and a charge of +2. Alpha particles are represented as 4He2. When 238U92 becomes 234Th90, it emitted a helium nucleus 4He2. The equation for the decay is 238U92 ---> 234Th90 + 4He2.