What do u mean by this
Like do u want the name of it?
I think it shows how the temperature of a substance changes when heated
Hi, there!
The answer to your question is as follows:
Given that the valence electrons were removed or added to the following elements to fulfill the octet, barium's charge would be +2, iodine's -1, potassium's +1, and aluminum's +3.
I hope this helps!
Answer: <em>The number placed in front of a compound to balance a chemical reaction is called </em><em><u>coefficient</u></em>.
Explanation:
Assume this general form for a <em>chemical equation</em>:
- <em>a</em>A + <em>b</em>B → <em>c</em>C + <em>d</em>D
The letters <em>a, b, c, </em>and <em>d,</em> in front of each compound A, B, C, and D, are called coefficients and indicate the number of formula units (molecules or ions) that take part in the equation.
Those coefficients are needed to <em>balance the equation</em> and ensure compliance with the law of mass conservation.
This example shows it:
- Word equation: hydrogen + oxygen yields water
- Chemical equation: H₂ (g) + O₂(g) → H₂O(g)
- Balance, adding the coefficients so that the number of each kind of atoms is the same on the left and the right of the chemical equation:
H₂ (g) + 2O₂(g) → 2H₂O(g)
In that equation:
- The coefficient of H₂ (g) on the left is 1 (it is not written)
- The coefficient of O₂(g) on the left is 2
- The coefficient of H₂O(g) on the right is 2
You read it as: 1 mole of gaseous hydrogen and 2 moles of gaseous oxygen yield 2 moles of water vapor.
Answer:
Kₐ = 5.7 x 10⁻⁵
Explanation:
The equilbrium for this acid is
HC₃H₃CO₂ + H2O ⇄ H₃O⁺ + C₃H₃CO₂ ⁻ ,
and the equilibrium constant for acrylic acid is given by the expression:
Kₐ = [ H₃O⁺][ C₃H₃CO₂⁻ ] / [ HC₃H₃CO₂ ]
Since the pH of the 0.23 M solution is known , we can calculate [ H₃O⁺].
The ][ C₃H₃CO₂⁻ ] is equal to [ H₃O⁺] from the above equilibria (1:1)
Finally [ HC₃H₃CO₂ ] is known.
pH = - log [ H₃O⁺]
taking antilog to both sides of the equation
10^-pH = [ H₃O⁺]
Substituting
10^-2.44 = [ H₃O⁺] = 3.6 x 10⁻³
[ C₃H₃CO₂⁻ ] = 3.6 x 10⁻³
Kₐ = ( 3.6 x 10⁻³ ) /0 .23 = 5.7 x 10⁻⁵
