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alex41 [277]
3 years ago
13

Environmental science-

Chemistry
2 answers:
Igoryamba3 years ago
8 0

Answer:

it's D

Explanation:

I took the test earlier

Lubov Fominskaja [6]3 years ago
7 0

Answer:

D

Explanation:

Logistic growth curves increase exponentially at first, then experience slowed growth rates. Hope your question works well!!!

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A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris
Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is 15.66J/^oC

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.473 moles

\Delta H_{rxn} = enthalpy change of the reaction  = -1235 kJ/mol = -1235\times 10^3J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J

To calculate the heat capacity of calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed by the calorimeter = 584.16\times 10^3J

c = heat capacity = ?

\Delta T = change in temperature = T_2-T_1=62.3^oC-25^oC=37.3^oC

Putting values in above equation, we get:

584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC

Hence, the heat capacity of calorimeter is 15.66J/^oC

4 0
4 years ago
Nitrogen monoxide is produced by combustion in an automobile engine. What volume of oxygen gas is required to react completely w
Dmitrij [34]

Answer:

qwertyuiopasdfghjkl;Zxcvbnm,zxfbfa

Explanation:

5 0
3 years ago
Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equatio
kkurt [141]
The equation is as follow,

<span>                                  HBr </span>₍aq₎  +  H₂O ₍l₎    →

Solution:
             HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,

                      HBr ₍aq₎  +  H₂O ₍l₎    →    H₃O⁺ ₍aq₎  +  Br⁻ ₍aq₎
8 0
4 years ago
The density of a pure substance is its mass per unit volume. The density of cresol has been measured to be 1024 g/L . Calculate
Ierofanga [76]

Answer: The mass of 405 ml of cresol is 415 grams

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{volume}

Given : Density of cresol = 1024 g/L

Volume of cresol = 405 ml = 0.405 L   ( 1L=1000ml)

Putting in the values we get:

1024g/L=\frac{mass}{0.405L}

mass=1024g/L\times 0.405L=415g

Thus mass of 405 ml of cresol is 415 grams

3 0
3 years ago
A sample of ideal gas is in a sealed container. The pressure of the gas is 705 torr , and the temperature is 19 ∘C . If the temp
posledela
808.77torr or 1.064atm
8 0
3 years ago
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