2. What does the term reflection mean?

What mathematical relationship between variables is suggested by a graph showing a diagonal line from the lower left to the uppe

Tresset [83]

Answer:

Direct proportionality

Explanation:

The graph of variables that are directly proportional such as the temperature and volume of a gas has a graph consisting of a diagonal line that from the lower left of the graph to the upper right of the graph

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature in Kelvin at constant pressure

Charles law can be represented mathematically as V ∝ T

From which we have;

V₁/T₁ = V₂/T₂, therefore, the graph of V to T has a constant slope, ΔV/ΔT.

4 0

3 years ago

glass shattering in to pieces bubblegum being stretched a piece of metal expanding due to heat These are all examples of Questio

kogti [31]

I think it’s physical change, because the objects aren’t changing into another substance, just changing their physical shape. Hope this helps!

4 0

3 years ago

Read 2 more answers

Please help me with my physics! I don not understand and please provide work.

den301095 [7]

4) B) Speed = Distance/ time
5) C) By applying second law of newton " F = ma" we say that "15 = 12 × acceleration"
15/12= acceleration
acceleration = 1.25 m/s2
6) D) It will continue to accelerate to the right but at a slower rate because of the small force (F2) being applied from the right.

7 0

4 years ago

A student at the top of a building of height h throws ball A straight upward with speed v0 (3 m/s) and throws ball B straight do

Flauer [41]

Answer:same

Explanation:

Given

ball A initial velocity=3 m/s(upward)

Ball B initial velocity=3 m/s (downward)

Acceleration on both the balls will be acceleration due to gravity which will be downward in direction

Both acceleration is equal

For ball A

maximum height reached is $h_1=\frac{3^2}{2g}$

After that it starts to move downwards

thus ball have to travel a distance of h_1+h(building height)

so ball A final velocity when it reaches the ground is

$v_a^2=2g\left ( h_1+h\right )$

$v_a^2=2g\left ( 0.458+h\right )$

$v_a=\sqrt{2g\left ( 0.458+h\right )}$

For ball b

$v_b^2-\left ( 3\right )^2=2g\left ( h\right )$

$v_b^2=2g\left ( \frac{3^2}{2g}+h\right )$

$v_b=\sqrt{2g\left ( 0.458+h\right )}$

thus $v_a=v_b$

5 0

3 years ago

A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin

kap26 [50]

Answer:

a) $\omega \approx 219.911\,\frac{rad}{s}$ , b) $\alpha = 16.916\,\frac{rad}{s^{2}}$ , c) $a_{t} = 1.776\,\frac{m}{s^{2}}$ , d) $a_{n} = 5077.889\,\frac{m}{s^{2}}$ , e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) $v = 23.091\,\frac{m}{s}$ .

Explanation:

a) The maximum angular velocity of the fan is:

$\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$\omega \approx 219.911\,\frac{rad}{s}$

b) The angular acceleration of the fan is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}$

$\alpha = 16.916\,\frac{rad}{s^{2}}$

c) The magnitude of the tangential aceleration is:

$a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)$

$a_{t} = 1.776\,\frac{m}{s^{2}}$

d) The magnitude of the centripetal acceleration is:

$a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)$

$a_{n} = 5077.889\,\frac{m}{s^{2}}$

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

$v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)$

$v = 23.091\,\frac{m}{s}$

5 0

3 years ago