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Goryan [66]
3 years ago
7

A pendulum on earth swings with angular frequency ω. On an unknown planet, it swings with angular frequency ω/ 4. The accelerati

on due to gravity on this planet is A pendulum on earth swings with angular frequency . On an unknown planet, it swings with angular frequency 4. The acceleration due to gravity on this planet is a. 16 g. b. 4 g.c. g/4. d. g/16 .
Physics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

g / 16

Explanation:

T = 2π \sqrt{\frac{l}{g} }

angular frequency ω = 2π /T

= \sqrt{\frac{g}{l} }

ω₁ /ω₂ = \sqrt{\frac{g_1}{g_2} }

Putting the values

ω₁ = ω ,     ω₂ = ω / 4

ω₁ /ω₂ = 4

4 =  \sqrt{\frac{g}{g_2} }

g₂ = g / 16

option d is correct.

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Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
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Explanation:

It is given that,

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The negative sign indicates that x and y are decreasing.

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        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

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So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

                       = \frac{-140 - 120}{5}

                       = 52

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7 0
3 years ago
What does critical mean?
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5 0
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Indicate whether the statement is true or false. The point located at the geometric center of an object is called the object's c
zmey [24]
This statement is true. The point located at the geometric center of an object is indeed called the object's center of gravity. Center of gravity is the average of the weight of a resultant of the parallel forces, including all the particles that is passing through its body.
4 0
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Why is it that the weight of an object weighing 1N air, weighs more when immersed in water ?
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exactly the opposite. 

Whatever the weight of a solid object is in air, that weight will appear
to be LESS when the object is immersed in water.

The object is lifted by a force equal to the weight of the fluid it displaces.
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4 0
3 years ago
We decided to make an iced latte by adding ice to a 200 mL hot latte at 45 °C. The ice starts out at 0 C. How much ice do we nee
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Answer:

m = 77.75 g

Explanation:

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m = 77.75 g

6 0
2 years ago
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