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zavuch27 [327]
3 years ago
14

Why don't ring particles form a moon? a. They collide too violently to accrete into a moon. b. Tidal forces from moons prevent t

hem from accreting. c. Tidal forces from the planet prevent them from accreting. d. Their masses are too small for them to accrete. e. They collide too infrequently to make a moon
Physics
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

c)Tidal forces from the planet prevent them from accreting.

Explanation:

According to the Roche limit and Hill spheres limit Saturn's rings are too close to the planet. This causes the tidal forces to tear the particles i.e., accretion will not start.

This can be even noticed in the rings itself. The C ring of Saturn which is closer to the planet has unclumped particles while in the B ring you can observe clumping.

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Answer: 17.68 s

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:  

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)  

Where:  

y=0 is the height of the ball when it hits the ground  

y_{o}=70 m is the initial height of the ball

V_{o}=82m/s is the initial velocity of the ball  

t is the time when the ball strikes the ground

g=9.8m/s^{2} is the acceleration due to gravity  

Having this clear, let's find t from (1):  

0=70m+(82m/s)t-\frac{1}{2}(9.8m/s^{2})t^{2} (2)  

Rewritting (2):

-\frac{1}{2}(9.8m/s^{2})t^{2}+(82m/s)t+70m=0 (3)  

This is a quadratic equation (also called equation of the second degree) of the form at^{2}+bt+c=0, which can be solved with the following formula:

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}  (4)

Where:

a=-\frac{1}{2}(9.8m/s^{2}

b=82m/s

c=70m

Substituting the known values:

t=\frac{-82 \pm \sqrt{82^{2}-4(-\frac{1}{2}(9.8)(70)}}{2a}  (5)

Solving (5) we find the positive result is:

t=17.68 s

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