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Triss [41]
2 years ago
15

Sound intensity, I, from a spherical source is a function of the distance, r, from the source of the sound. It is represented by

the function uppercase I
Physics
1 answer:
quester [9]2 years ago
8 0

A study assessing the effect of anxiety Sound intensity, I, from a spherical source is a function of the distance, r, from the source of the sound.

Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our physical spherical. Anxiety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are spherical ready for a challenging situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, spherical with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have indicated that female students have greater levels of test anxiety than male students.

Learn more about anxiety here:

brainly.com/question/4913240

#SPJ4

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ki77a [65]

Answer:B

Explanation:

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4 years ago
Does the universe have centre?​
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No it does not ...hope this helps
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3 years ago
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We can reasonably model a 90-W incandescent lightbulb as a sphere 7.0cm in diameter. Typically, only about 5% of the energy goes
Ronch [10]

Answer:

292.3254055 W/m²

469.26267 V/m

1.56421\times 10^{-6}\ T

Explanation:

P = Power of bulb = 90 W

d = Diameter of bulb = 7 cm

r = Radius = \frac{d}{2}=\frac{7}{2}=3.5\ cm

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

c = Speed of light = 3\times 10^8\ m/s

The intensity is given by

I=\frac{P}{A}\\\Rightarrow I=\frac{90}{4\pi 0.035^2}\\\Rightarrow I=5846.50811\ W/m^2

5% of this energy goes to the visible light so the intensity is

I=0.05\times 5846.50811\\\Rightarrow I=292.3254055\ W/m^2

The visible light intensity at the surface of the bulb is 292.3254055 W/m²

Energy density of the wave is

u=\frac{1}{2}\epsilon_0E^2

Energy density is also given by

\frac{I}{c}=\frac{1}{2}\epsilon_0E^2\\\Rightarrow E=\sqrt{\frac{2I}{c\epsilon_0}}\\\Rightarrow E=\sqrt{\frac{2\times 292.3254055}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E=469.26267\ V/m

The amplitude of the electric field at this surface is 469.26267 V/m

Amplitude of a magnetic field is given by

B=\frac{E}{c}\\\Rightarrow B=\frac{469.26267}{3\times 10^8}\\\Rightarrow B=1.56421\times 10^{-6}\ T

The amplitude of the magnetic field at this surface is 1.56421\times 10^{-6}\ T

7 0
3 years ago
A particle is traveling in the positive direction along an x axis, at a constant 5 m/s. Which of the following describes the par
vaieri [72.5K]
1-zero as the velocity is constant
3 0
3 years ago
Please help on this one?
lisov135 [29]

Answer:

The current in a resistor decreases by a factor of 4.

Explanation:

I = \frac{E}{R}

Where (I) is the current, (E) is the voltage and (R) is the resistance.

Decreasing the voltage by 4 gives;

I = 0.25\frac{E}{R}

Since you have multiplied \frac{E}{R} by 0.25,

You have to multiply I by 0.25 so the current decreases by a factor of 4.

3 0
3 years ago
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