The right answer for the question that is being asked and shown above is that: "C) carbon monoxide and carbon dioxide" hydrocarbons burn completely in an excess of oxygen, the products are <span>C) carbon monoxide and carbon dioxide</span>
Oxidation of D-glucose are usually found on the photosynthesis which has a by product of carbon dioxide (CO2) and water (H2O) chemically written as,
C6H12O6 +6O2----> 6CO2 +6H2O
Moreover, D-glucose can also be chemically react with oxygen to form D-gluconic acid and D-glucoronic acid.
I would say that the density increases because the distance between the molecules decreases, and therefore becomes smaller, and vice versa the density increases, and that is a physical change not a chemical change.
Answer: 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Explanation:
To calculate the moles :
According to stoichiometry :
As 2 moles of octane give = 16 moles of
Thus 3.07 moles of octane will give = of
Mass of
Thus 1082 g of carbon dioxide are produced for every 350 grams of octane reacted in the engine
Taking into account the reaction stoichiometry, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 AgC₂H₃O₂ + K₂CrO₄ → Ag₂CrO₄ + 2 KC₂H₃O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- AgC₂H₃O₂: 2 moles
- K₂CrO₄: 1 mole
- Ag₂CrO₄: 1 mole
- KC₂H₃O₂: 2 moles
<h3>Moles of Ag₂CrO₄ formed</h3>
By reaction stoichiometry 2 moles of AgC₂H₃O₂ form 1 mole of Ag₂CrO₄.
In other words, according to this balanced chemical equation, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.
Learn more about the reaction stoichiometry:
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