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ICE Princess25 [194]
3 years ago
5

If given a device that has unknown circuitry, and you measure that the voltage across the device leads the voltage across a resi

stor at 500 Hz, can you know what type of elements are in the device?
Physics
1 answer:
shusha [124]3 years ago
7 0

There may be an improper voltage in the device.                                                                                                                                                              

<u>Explanation</u>:

  • Given the device has unknown circuitry and the voltage across the device crosses the voltage across the resistor at 500 Hz. In this device, the current flow is not correct. It is improper.
  • The elements in the device are ammeter, capacitor, inductor, voltmeter, and battery. The components in the device may not be connected properly. This is due to the improper flow of current and condition of the voltmeter.
  • So these are the type of elements in the device.

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The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank
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A car travels 300 km in the first 3 hours of a trip. Then it hits traffic and travels only 60 km during the last hour. What is the average speed of the of the car?


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4 years ago
An air conditioner runs 15 minutes each hour on a hot summer day. It is on a 240 volt circuit and uses 21 amps. Rate is $.10/kWh
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Answer:

Approximately \$ 3.02.

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Note that the electric rate in this question is in the unit dollar-per-{\rm kWh}, where 1\; {\rm kWh} is the energy to run an appliance of power 1\; {\rm kW} for an hour.

Number of minutes for which the air conditioner is running in that day: 15 \times 24 = 360\; \text{minute}. Apply unit conversion and ensure that this time is measured in hours (same as the unit of the electric rate.)

\begin{aligned} \text{time} &= 360\; \text{minute} \times \frac{1\; \text{hour}}{60\; \text{minute}} = 6\; \text{hour} \end{aligned}.

The power of this air conditioner is:

\begin{aligned} \text{power} &= \text{voltage} \times \text{current} \\ &= 240\; {\rm V} \times 21\; {\rm A} \\ &= 5040\; {\rm W} \\ &= 5.04\; {\rm kW} \end{aligned}.

Thus, the energy that this air conditioner would consume would be:

\begin{aligned}\text{energy} &= \text{power} \times \text{time} \\ &= 5.04\; {\rm kW} \times 6\; \text{hour} \\ &= 30.24\; {\rm kWh} \end{aligned}.

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