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Nana76 [90]
3 years ago
10

Two masses m1 and m2 are traveling in the direction of each other. The speed of m1 is v1 and oriented along the positive x-direc

tion, while that of m2 is v2 and oriented along the negative x-direction. The masses are such that m1 = m2/10.
A) If the two masses stick together, in what direction do they travel after they impact?
i. to the left
ii. not enough information
iii. to the right
iv. they will stop at the point where they collide
Physics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

feelsbadman

Explanation:

feels

bad

man

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Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
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calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2​
igor_vitrenko [27]

First, balance the reaction:

_ KClO₃   ==>   _ KCl + _ O₂

As is, there are 3 O's on the left and 2 O's on the right, so there needs to be a 2:3 ratio of KClO₃ to O₂. Then there are 2 K's and 2 Cl's among the reactants, so we have a 1:1 ratio of KClO₃ to KCl :

2 KClO₃   ==>   2 KCl + 3 O₂

Since we start with a known quantity of O₂, let's divide each coefficient by 3.

2/3 KClO₃   ==>   2/3 KCl + O₂

Next, look up the molar masses of each element involved:

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• Cl: 35.453 g/mol

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Convert 10 g of O₂ to moles:

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The balanced reaction shows that we need 2/3 mol KClO₃ for every mole of O₂. So to produce 10 g of O₂, we need

(2/3 (mol KClO₃)/(mol O₂)) × (0.31252 mol O₂) ≈ 0.20835 mol KClO₃

KClO₃ has a total molar mass of about 122.549 g/mol. Then the reaction requires a mass of

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