Question

a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we neglect air friction, how high is the cliff

Answer 1

Answer:

we use the formula,

$v {}^{2} = u {}^{2} + 2gh$

$89 {}^{2} = 76 {}^{2} + 2(10)h$

$h = (89 {}^{2} - 76 {}^{2} ) \div 20$

h= 107 m