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Natasha2012 [34]
3 years ago
5

a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n

eglect air friction, how high is the cliff
Physics
1 answer:
RSB [31]3 years ago
5 0

Answer:

we use the formula,

v {}^{2}  = u {}^{2}  + 2gh

89 {}^{2}  = 76 {}^{2}  + 2(10)h

h = (89 {}^{2}  - 76 {}^{2} ) \div 20

h= 107 m

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28. A stone is projected at a cliff of height h with an initial speed of 42.0 mls directed at angle θ0 = 60.0° above the horizon
Julli [10]

Answer:

a) 51.8 m, b) 27.4 m/s, c) 142 m

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h, v, and H

a) y = y₀ + v₀ᵧ t + ½ gt²

0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²

h = 51.8 m

b) vᵧ = gt + v₀ᵧ

vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)

vᵧ = -17.5 m/s

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vₓ = 21.0 m/s

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v = 27.4 m/s

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4 0
3 years ago
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