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bija089 [108]
3 years ago
6

The law of definite proportions helps us explain why water will always        A. break down into gas when heated.   B. be releas

ed or used up in a chemical reaction.   C. be used as a solvent to dissolve other compounds.   D. consist of a particular proportion of hydrogen and oxygen.
Chemistry
2 answers:
NikAS [45]3 years ago
8 0
... liquid water are two different forms of the same chemical substance, water. A chemical substance is a form of matter that has constant chemical ...
defon3 years ago
6 0

The correct answer is:

D.  consist of a particular proportion of hydrogen and oxygen.


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Only some particles split up into smaller particles
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Everything around you can be broken down into smaller particles called atoms. The particles of one substance are all the same and different substances are made up of different particles.

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What changes occur in O + O = O2
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They went from atoms to oxygen molecule.

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I'm not sure if this is the answer your teacher is looking for, but in simple terms you had 2 oxygen atoms. Together they make an oxygen molecule, which is the stuff we breathe.

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What would happen to other populations if they didn't have limitng factors?
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3 years ago
What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
1 year ago
What do hydroligists primarly study
serious [3.7K]

Answer:

The study of movement, distribution and quality of water.

Explanation:

They measure the properties of bodied of water, such as the volume of and stream flow.

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