The answer is 0.25 M
Use the equation C1V1=C2V2
(.5)(100)=x(200)
x=0.25
Answer:
A
Explanation:
Chlorine has one valence electron
Hence one chlorine atom reacts with 2 atoms of lithium
And also reacts with 3 atoms of boron
<span>0.0797 g
Looking at the formula, 1 mole of KIO3 and 5 moles of KI will react and produce moles of iodine molecules or 6 moles of iodine atoms. So first, determine the number of moles of KIO3 and KI provided
moles KIO3 = 0.0121 * 0.097 = 0.0011737 mol
moles KI = 0.0308 * 0.017 = 0.0005236 mol
The limiting reactant is KI at 0.0005236 mol so divide by 5 and multiply by 6 to get the number of moles of iodine atoms.
0.0005236 / 5 * 6 = 0.00062832 mol
Lookup the atomic weight of iodine which is 126.90447
And multiply that by the number of moles of iodine produced
126.90447 g/mol * 0.00062832 mol = 0.079736617 g
Rounding to 4 decimal places gives 0.0797 g</span>
[H+] = ?
pH = -log[H+]
[H+] = 10^-pH
[H+] = 10^-11,3
[H+] = 5,01 × 10^-12 mol/l
Answer: H+ concentration in this solution equal 5,01 × 10^-12 mol/l.
:-) ;-)
