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Crazy boy [7]
3 years ago
12

For Laminar flow conditions, what size pipe will deliver 90 gpm of medium oil at 40°F (υ = 6.55 * 10^‐5)?

Engineering
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

1.693 feet

Explanation:

We have given Q = 90 gpm

We know that 1 cubic feet per second = 443.833 gpm

So 90 gpm will be equal to \frac{90}{443.833}=0.202\frac{ft^3}{sec}

Let d is the diameter of the pipe then V_{avg}=\frac{Q}{A}=\frac{0.2}{\frac{\pi }{4}d^2}=\frac{0.255}{d^2}

We know that for pipe flow critical Reynolds number =2300

So \frac{V_{avg}d}{\nu }=2300

Value of \nu is 6.55\times 10^{-5} given in question

So \frac{0.255\times d}{d^2\times 6.5\times 10^{-5}}=2300

d=1.693 feet  

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Answer:

b) false

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Along with above 4 processes intake and exhaust processes are parallel to each other.From the P-v diagram we can see that all processes.

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4 0
3 years ago
Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW o
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Complete Question

Complete Question is attached below.

Answer:

V'=5m/s

Explanation:

From the question we are told that:

Diameter d=0.10m

Power P=4.0kW

Head loss \mu=10m

 \frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu

 \frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10

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Generally the equation for Power is mathematically given by

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Therefore

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 Q=AV'

Where

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 A=7.85*10^{-3}

Therefore

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snow_tiger [21]

Answer:

D=0.41m

Explanation:

From the question we are told that:

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