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Inessa [10]
3 years ago
14

What is the formula for calculating the length of the space diagonal of a right rectangular prism on the basis of the prism's?

Mathematics
1 answer:
disa [49]3 years ago
7 0
It is A^2+B^2+C^2 = D^2
You might be interested in
Find the number that must be added to each expression to form a perfect square trinomial. Then write the trinomial as a binomial
maksim [4K]
<h2>Hello!</h2>

The answers are:

a) \frac{49}{4}

b) (x+\frac{7}{2})^{2}

<h2>Why?</h2>

First, we need to know that for this case:

a=1\\2ab=7

So,

b=\frac{7}{2}

b^{2} =(\frac{7}{2})^{2}=\frac{49}{4}

We must add \frac{49}{4}  to the expression in order to form a perfect square trinomial,

x^{2} +7x+\frac{49}{4}

Writing the trinomial as a binomial square:

(x+\frac{7}{2})^{2}=x^{2}+2*\frac{7}{2}*x+(\frac{7}{2})^{2}=x^{2} +7x+\frac{49}{4}

Have a nice day!

8 0
3 years ago
Read 2 more answers
Warm-Up
PtichkaEL [24]

Answer:

The w in w² + 5·w → Variable

The 2 in w² + 5·w → Exponent

The 5 in w² + 5·w → Coefficient

Step-by-step explanation:

1) The variable in an equation are the unknown values of the equation, and the values of the variables that meet the requirements of the equality are known as the solutions of the equations;

2) The exponent is the power to which a number or a variable is raised. It shows the number of times the variable or number multiples itself

3) The coefficient is the factor multiplying the variable in an equation or expression.

5 0
3 years ago
Perpendicular Vectors:
klemol [59]
1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
Answer: D )
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
Answer: C )
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >,  yes.
3 0
3 years ago
Solve these and show your work pls!
sertanlavr [38]

Answer :the 1st and 3rd are true

Step-by-step explanation:

you do the math how their set up so just right those and you can get your answer that way. (if your adding a positive and negative your basically subtracting so just write in the order their in; if you subtracting a negative from a positive it equals a positive; if your subtracting a negative from a negative or the answer is positive; if your subtracting a positive from a negative its negative) i hope this helps if u have any more questions just message me and i  will be happy to help you anytime!!! <3

3 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
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