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3 years ago

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The compound gallium iodide, is often used in creating crystals for computer chips. Which of the following best describes the ch

emical formula of gallium iodide? A. GaI B. Ga3I C. Ga2I3 D. GaI3

1 answer:

True [87]3 years ago

5 0

D. GaI₃

Explanation:

In gallium iodide GaI₃, gallium is stabilized with the oxidation number +3 so it will need three iodine atoms with oxidation number -1.

Gallium iodide is also found in a dimer form Ga₂I₆.

Learn more about:

Gallium

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john throws .4 kg ball with velocity of 18 m/s. Hits .2 kg bottle and bottle flies 25 m/s. How fast is ball traveling after hitt

UNO [17]

Answer:

5.5 m/s

Explanation:

Assuming the bottle is initially stationary, we can write the law of conservation of momentum as follows:

$p_i = p_f\\m_b u_b = m_b v_b + m_B v_B$

where

$m_b = 0.4 kg$ is the mass of the ball

$u_b = 18 m/s$ is the initial velocity of the ball

$m_B = 0.2 kg$ is the mass of the bottle

$v_B = 25 m/s$ is the final velocity of the bottle

$v_b$ is the final velocity of the ball

Solving for $v_b$ ,

$v_b = \frac{m_b u_b - m_B v_B}{m_b}=\frac{(0.4 kg)(18 m/s)-(0.2 kg)(25 m/s)}{0.4 kg}=5.5 m/s$

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3 years ago

A mule is harnessed to a sled having a mass of 246 kg, including supplies. The mule must exert a force exceeding 1210 N at an an

zimovet [89]

(a) 1800 N

The equation of the forces along the vertical direction is:

$F sin \theta + N - mg = 0$

where

$F sin \theta$ is the component of the applied force along the vertical direction

N is the normal force on the sled

mg is the weight of the sled

Substituting:

F = 1210 N

m = 246 kg

$\theta = 30.3^{\circ}$

We find N:

$N=mg-F sin \theta = (246)(9.8)-(1210)(sin 30.3^{\circ})=1800 N$

(b) 0.580

The equation of the forces along the horizontal direction is:

$F cos \theta - \mu_s N = 0$

where

$F cos \theta$ is the horizontal component of the push applied by the mule

$\mu_s N$ is the static frictional force

Substituting:

F = 1210 N

N = 1800 N

$\theta = 30.3^{\circ}$

We find $\mu_s$ , the coefficient of static friction:

$\mu_s = \frac{F cos \theta}{N}=\frac{(1210)(cos 30.3^{\circ})}{1800}=0.580$

(c) 522 N

In this case, the force exerted by the mule is

$F= 6.05 \cdot 10^2 N = 605 N$

So now the equation of the forces along the horizontal direction can be written as

$F cos \theta - F_f = 0$

where

$\theta=30.3^{\circ}$

and $F_f$ is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value $\mu N$ , depending on how much force is applied in the opposite direction)

Solving the equation,

$F_f = F cos \theta = (605)(cos 30.3^{\circ})=522 N$

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3 years ago

A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ

Neporo4naja [7]

Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
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3 years ago

During destructive interference, two waves moving through the same medium will

ddd [48]

They will amplify eachother.

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3 years ago

Read 2 more answers

The thread around a screw is a lever.

monitta

It's a plain, not a lever

7 0

4 years ago