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Aneli [31]
3 years ago
15

3. The impulse necessary to change the momentum of an object by 5 kgm/s is:

Physics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

Impulse, J = 5 kg-m/s

Explanation:

Accoding to impulse-momentum theorem, the change in momentum of an object is equal to the impulse applied to it. In this problem, the change in momentum of an object is 5 kg-m/s.

We need to find the impulse necessary to change the momentum. So, impulse will be equal to 5 kg-m/s.

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At a certain point on a heated metal plate, the greatest rate of temperature increase, 3 degrees Celsius per meter, is toward th
Katena32 [7]

Explanation:

Formula to determine the rate of temperature increasing will be calculated as follows.

              D_{u}F = \Delta F.\vec{u}

                       = |\Delta F|.|j| cos \theta

                       = 3.|1|.cos(\frac{\pi}{4})

                       = 3 \times \frac{1}{\sqrt{2}}

                       = \frac{3 \sqrt{2}}{2}

                       = 2.121

Thus, we can conclude that the rate at which the temperature increasing is 2.121.

3 0
3 years ago
Read 2 more answers
Please fast answerrr thank you​
Vedmedyk [2.9K]

Answer:

50J

Explanation:

At the top you have(A)

KE_a = O

PE_a = 100J

KE + PE = 100J

At the bottom you have (C)

KE_c= 100J

PE_c=0J

KE+PE = 100J

At point C:

You are at half the height.

We know that at H, PE =100J

PE_c = mgH

At C,

PE_c= mg (H/2) *at half the height

*m and g stay the same

Intuitively, the higher you are, the more potential energy you have.

If you decrease the height by a half, your PE will also decrease

At A:

PE_a / (mg) = H

At B:

PE_b / (mg) = H/2

to also get H on the right hand side, multiply by 2

2 (PE_b/ (mg))= H

2PE_b / (mg) = H

Ok, now that we have set up 2 equations (where H is isolated), find PE at B

AT A = AT B *This way you are saying that H = H (you compare both equations)

PE_a / (mg) = 2x PE_b / (mg)

*mg are the same for both cancel them (you can do that because of the = sign)

PE_a =  2PE_b

We know that PE_a = 100J

100J/2 = PE_b

PE at b = 50J

**FIND KE at b

We know that

KE_b + PE_b is always 100J

100J = 50J + KE_b

KE_b = 50J

4 0
2 years ago
What was the greatest discovery by galileo during his inclined-plane experiments?
Sergeeva-Olga [200]
Galileo discovered during his inclined-plane experiments that a ball rolling down an incline and onto a horizontal surface would roll indefinitely.
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3 years ago
CAN SOME ONE TALK TO ME PLZ ASAP IM GOING THROUGH A BAD TIME
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3 years ago
A bicycle is ridden along a horizontal road with a driving force of 400, n,400n. its speed is constant at 12, m, slash, s,12m/s.
mr_godi [17]

The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

<h3>What is friction force?</h3>

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

Learn more about friction force.

brainly.com/question/1714663

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2 years ago
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