A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?

Newton's first law of motion is the law of inertia

saw5 [17]

Answer:

this statement is true because I looked it up

7 0

3 years ago

Read 2 more answers

A farm truck travels due east with a constant speed of 9.50 m/s along a horizontal road. A boy riding in the back of the truck t

Reil [10]

Answer:

a)he angle is 90 with respect to the horizontal (x axis)

b) its speed is zero both vertically and horizontally

c) vertical path

d) a parabolic movement

e) v₀ = (9.5i ^ + 8.232 j ^) m / s

Explanation:

This is a relative problem and movement.

.v ’= v + u

Where v ’is the speed with respect to the mobile system, v the speed with respect to the fixed system and the speed between the two reference systems

a) The child and the can is in the truck, so they go at the speed of the truck, when he throws the can he continues at this speed on the x-axis and therefore as the two advance the same distance the more hands of the child, consequently the can is thrown vertically

The angle is 90 with respect to the horizontal (x axis)

b) with respect to the truck, the can is still, so its speed is zero both vertically and horizontally

c) The child sees that the can follows a vertical path

d) A stationary observer on the ground, sees that the can has a constant speed in the same direction of the truck and when they throw it vertical goal has a vertical movement, the sum of these two movements gives a parabolic movement of the same uncle as a projectile launch

e) the initial speed has two components

X Axis v_lata = v_camion = 9.5 m / s

Y Axis speed given by the child

Let's look for the travel time

x = v₀ₓ t

t = x / v₀ₓ

t = 16 / 9.5

t = 1.68 s

y = $v_{oy}$ t - ½ g t²

When he returns to the child's hand and = 0

0 = v_{oy} t - ½ g t²

v_{oy} = ½ g t

v_{oy} = ½ 9.8 1.68

v_{oy} = 8,232 m / s

Speed is

v₀ = (9.5i ^ + 8.232 j ^) m / s

5 0

3 years ago

A rock is thrown at an angle of 30 degrees above the horizontal with initial velocity 15m/s what is the displacement when the ro

Delvig [45]

The displacement of the rock will be the same as the total horizontal distance traveled. Here the rock's horizontal position is given by

$x=\left(15\,\dfrac{\mathrm m}{\mathrm s}\right)\cos30^\circ\,t$

so to find the horizontal distance it traversed, we need to know the time it took for the rock to return to the ground. We use the rock's vertical position over time to figure that out:

$y=\left(15\,\dfrac{\mathrm m}{\mathrm s}\right)\sin30^\circ\,t-\dfrac g2t^2=0$

where $g=9.8\,\dfrac{\mathrm m}{\mathrm s^2}$ is the acceleration due to gravity. Then we find that $t\approx1.5\,\mathrm s$ , at which point we find $x\approx20\,\mathrm m$ .