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3 years ago

janet completed 8 math problems in 10 minutes. How long per question did janet spend(in minutes and seconds)?

Mathematics

2 answers:

Dominik [7]3 years ago

5 0

It would take 1.25 minutes to complete each problem because 10 divided by 8 equals 1.25

Xelga [282]3 years ago

5 0

Answer:1.25 minutes

Step-by-step explanation:

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SashulF [63]

A ∩ B = {3, 6, 9, 12} ∩ {2, 4, 6, 8, 10, 12}
= {6, 12}

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A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra

Ksivusya [100]

The Quadrilateral is JKLM,

let $M_{JK}, M_{KL}, M_{LM}, M_{JM},$ be the midpoints of JK, KL, LM and JM respectively.

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Given any 2 point P(m,n) and Q(k,l),<span>

the coordinates of the midpoint of the line segment PQ are given by the formula:

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thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

are as follows:

$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

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thus the distances connecting the opposite entrances can be calculated as follows:

$|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5$

$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

Thus the total distance of the paths joining the opposite entrances is

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

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3 years ago

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Lostsunrise [7]

Will ran 3.23 + 4.15 = 7.38 in those 2 weeks, which rounds up to 7.4 km.
Chuck ran 8.75, which rounds to 8.8.

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