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vesna_86 [32]
3 years ago
13

A car accelerates ( speeds up) uniformly from 5 m/s * t * o 15 m/s in 2 seconds, calculate the car's acceleration?

Physics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

0.4 ms-²

Explanation:

v = u+ at

15 = 5+ a×25

10/5 = a

a = 0.4 ms-²

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Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. T
diamong [38]

Answer:

Rate of heat is 45.1 kJ/min

Explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

L = 2.25 \times 10^6 J/kg

now we have

Q = (0.200)(2.25 \times 10^6 J/kg)

Q = 452.1 kJ

now the power is defined as rate of energy

P = \frac{Q}{t}

P = \frac{452.1 kJ}{10}

P = 45.1 kJ/min

6 0
3 years ago
Which process can transfer energy to a solid metal block
gladu [14]
Eneregy is the ability to to do work it takes work to heat someone heat is energy put the solid metal block in a campfire and heat it up tada wait, we need the options, nevermind
4 0
3 years ago
Read 2 more answers
They realize there is a thin film of oil on the surface of the puddle. If the index of refraction of the oil is 1.81, and they o
Sphinxa [80]

Answer:

The right solution is "165.8 nm".

Explanation:

Given:

Index of refraction,

n = 1.81

Wavelength,

λ = 600 nm

We know that,

⇒ t=\frac{\lambda}{2\times n}

By putting the values, we get

      =\frac{600}{2\times 1.81}

      =165.8 \ nm

3 0
3 years ago
Two charged objects have a repulsive force of .80 N. If the charge of one of the objects is doubled, then what is the new force?
sveticcg [70]
The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.
6 0
3 years ago
How much mass should be attached to a vertical ideal spring having a spring constant (force constant)of 39.5 N/m so that it will
nordsb [41]

Answer:

m = 1 kg

Explanation:

Given that,

The force constant of the spring, k = 39.5 N/m

The frequency of oscillation, f = 1 Hz

The frequency of oscillation is given by the formula as formula as follows :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f^2=\dfrac{k}{4m\pi^2}\\\\m=\dfrac{k}{4\pi^2 f^2}\\\\m=\dfrac{39.5}{4\pi^2 \times (1)^2}\\\\m=1\ kg

So, the mass that is attached to the spring is 1 kg.

6 0
2 years ago
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