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svlad2 [7]
4 years ago
10

At a fixed depth within a fluid at rest, the pressure pushing upward is

Physics
1 answer:
earnstyle [38]4 years ago
3 0

Answer: E) A) salt water.

Explanation:

E) In equilibrium, pressure exerts equally in all directions, so for a given depth, the pressure is the same for all points located at the same depth, and it can be written as follows:

p = p₀ + ρ.g.h, where p₀ = atmospheric pressure, ρ=fluid density, h=depth from the surface.

A) The buoyant force, as discovered by Archimedes, is an upward force, that opposes to the weight of an object (as it is always downward), and is equal to the weight of the volume of the liquid that the object removes, which means that is proportional to the density of the liquid.

As salt water is denser than fresh water, the buoyant force exerted by the salt water is always greater than the one produced by the fresh water, so objects will float more easily in salt water than in fresh water.

In the limit, it is possible that one object float in salt water and sink in fresh water.

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If the Sun suddenly turned off, we would not know it until its light stopped coming. How long would that be, given that the Sun
Yuliya22 [10]

Answer:

8.33 minutes

Explanation:

First let us find out how much time it takes for the light for the sun to reach the earth

Distance between Earth and Sun is 1.5×10¹¹ m

Speed of light = 3×10⁸ m/s

\text{Time taken}=\frac{1.5\times 10^{11}}{3\times 10^8}\\\Rightarrow \text{Time taken}=500\ seconds

Converting to minutes

500\ seconds=\frac{500}{60}=8.33\ minutes

So, it takes 8.33 minutes for the light from the sun to reach Earth.

This means that we would be receiving light for 8.33 minutes after the Sun turned off.

3 0
3 years ago
A laser beam is incident at an angle of 30.2° to the vertical onto a solution of corn syrup in water. (a) If the beam is refract
mote1985 [20]

Answer:

a) n2 = 1.55

b) 408.25 nm

c) 4.74*10^14 Hz

d) 1.93*10^8 m/s

Explanation:

a) To find the index of refraction of the syrup solution you use the Snell's law:

n_1sin\theta_1=n_2sin\theta_2   (1)

n1: index of refraction of air

n2: index of syrup solution

angle1: incidence angle

angle2: refraction angle

You replace the values of the parameter in (1) and calculate n2:

n_2=\frac{n_1sin\theta_1}{sin\theta_2}=\frac{(1)(sin30.2\°)}{sin18.82\°}=1.55

b) To fond the wavelength in the solution you use:

\frac{\lambda_2}{\lambda_1}=\frac{n_1}{n_2}\\\\\lambda_2=\lambda_1\frac{n_1}{n_2}=(632.8nm)\frac{1.00}{1.55}=408.25nm

c) The frequency of the wave in the solution is:

v=\lambda_2 f_2\\\\f_2=\frac{v}{\lambda_2}=\frac{c}{n_2\lambda_2}=\frac{3*10^8m/s}{(1.55)(408.25*10^{-9}m)}=4.74*10^{14}\ Hz

d) The speed in the solution is given by:

v=\frac{c}{n_2}=\frac{3*10^8m/s}{1.55}=1.93*10^8m/s

8 0
3 years ago
Which equation represents a neutralization reaction?
elixir [45]

B  acid + base    →  water + salt

Explanation:

The best equation that represents a neutralization reaction is:

                      acid + base    →  water + salt

In a neutralization reaction, an acid reacts with a base to produce salt and water only.

Here, hydrogen combines with hydroxide to form water.

Titration is usually used to carry out this reaction in the laboratory.

An indicator is added to the base and at end the color of the reaction changes.

At this point the acids have completely been neutralized with the base.

Learn more:

Neutralization brainly.com/question/4455839

#learnwithBrainly

5 0
3 years ago
How fast does a 2 MeV fission neutron travel through a reactor core?
Artemon [7]

Answer:

The answer is 1.956 \times 10^7\ m/s

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy E = mc^2, so the definition of energy in this case is

E = \frac{1}{2}m v^2.

From the last equation,

v= \sqrt{2E/m}

where

E = 2 MeV = 3.204 \times 10^{-13} J

and the mass of the neutron is

m = 1.675\times 10^{-27}\ Kg.

Then

v = 1.956 \times 10^7\ m/s

the equivalent of 0.065 the speed of light.

5 0
3 years ago
The temperature at one of the Viking sites on Mars was found to vary daily from -90.OF to -5.0 C. Convert these temperatures to
kykrilka [37]

Answer:

I don't know about this, this is which class question

6 0
3 years ago
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