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Rina8888 [55]
4 years ago
12

Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a d ensity of 16.6 g/cm3, and an atomic

weight of 180.9 g/mol.
Chemistry
1 answer:
Sidana [21]4 years ago
4 0

solution:

Ta is BCC, a=\frac{4}{\sqrt{3}r},n=2atoms/cell\\p=16.6gram/cm^3,A=180.9gram/mol\\P=\frac{A\times n}{N_{a}\times v}=\frac{180.9\frac{gram}{mol}\times 2 \frac{atom}{cell}}{6.023\times10^23\frac{atom}{mol}\times(\frac{4}{\sqrt{3}\times r})^3\frac{cm^3}{cell}}\\=16.6\frac{gram}{cm^3}\\r=(\frac{180.9\times2}{16.6\times6.023\times10^23\times(\frac{4}{\sqrt{3}})^3})^\frac{1}{3}\times10^8


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A 10.00 mL sample of vinegar (an aqueous solution of acetic acid) is titrated with 0.5062 M NaOH(aq) and 16.58 mL is required to
sammy [17]

Answer:

5.01%

Explanation:

Density of vinegar = mass/volume

Mass of 10.00 mL = density x volume

                           = 1.006 x 10 = 10.06 g

From the equation of reaction:

CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)

1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.

mole of NaOH = molarity x volume

                      = 0.5062 x 0.01658

                       = 0.008392796‬ mole

0.008392796‬ mole of NaOH will therefore require 0.008392796‬ mole of CH3COOH.

mass of CH3COOH = mole x molar mass

                                     = 0.008392796‬ x 60.052

                                      = 0.504 g

Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%

    = 5.01%

The percent by mass of acetic acid in the vinegar is 5.01%

3 0
3 years ago
Potassium carbonate dissolves as follows:
lara [203]

The 0.25 volume in liters of 1.0 M K_{2}CO_{3} solution is required to provide 0.5 moles of K(aq).

Calculation,

The Potassium carbonate dissolves as follows:

K_{2}CO_{3}(s) → 2K(aq) +CO_{3}^{-2} (aq)

The mole ratio is 1: 2

It means, the 1 mole K_{2}CO_{3} required to form 2 mole of K(aq).

To provide 0.5 mole of K(aq) = 1 mole ×0.5 mole /2 mole required by K_{2}CO_{3}.

To provide 0.5 mole of K(aq) ,0.25 mole required by K_{2}CO_{3}.

The morality of  K_{2}CO_{3} = 1 M = number of moles / volume in lit

The morality of  K_{2}CO_{3} =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

learn about moles

brainly.com/question/26416088

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5 0
2 years ago
How much heat (in kJ k J ) is evolved in converting 2.00 mol m o l of steam at 135 ∘C ∘ C to ice at -42 ∘C ∘ C ? The heat capaci
vovikov84 [41]

The total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

<h3>Heat evolved in converting the steam to ice</h3>

The total heat evolved is calculated as follows;

Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)

where;

  • Q is heat evolved

Q = = mcΔθ

where;

  • m is mass,  (mass of water = 18 g/mol)
  • c is specific heat capacity,
  • Δθ is change in temperature

Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)

Q(tot) = -12,928.68 J

Thus, the total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

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8 0
2 years ago
2) Convert 2.65*10^ ^ 25 atoms of Chlorine to moles of CI
Irina18 [472]

Answer:

22 mol

Explanation:

Given data:

Number of atoms of Cl = 2.65×10²⁵ atom

Number of moles of Cl = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.65×10²⁵ atom × 1 mol / 6.022 × 10²³ atoms

0.44×10² mol

22 mol

7 0
3 years ago
Is ineffective collision's the answer? Please correct me if not, thank you. :)
AleksAgata [21]
Yes! You're correct! Hope this helps! :D
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3 years ago
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