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olchik [2.2K]
3 years ago
11

The body's reaction to a change in the environment is called a response.

Chemistry
1 answer:
Rzqust [24]3 years ago
3 0
The first answer or “t” :)
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The balanced reaction equation for combustion of heptane, C7H16, is
Allisa [31]

Answer: m = 11.2 g C7H16

Explanation: First convert the mass of CO2 to moles. Then do the mole ratio between CO2 and C7H16 which is 7:1. Finally convert the moles of C7H16 to the mass of C7H16.

Solution attached.

3 0
3 years ago
Read 2 more answers
Which type of cloud would you expect the heaviest precipitation?
barxatty [35]

It is the nimbostratus cloud.  

4 0
3 years ago
if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As
Black_prince [1.1K]
Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture 
Na₂SO₄ ---> 2 Na⁺ + SO₄³⁻

1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions 

the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
                                                         = 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol

NaCl ----> Na⁺ + Cl⁻ 
1 mol of NaCl gives 1 mol of Na⁺ ions
number of NaCl moles added = 1.20 M/1000 * 200 ml
                                               = 0.24 mol
number of Na⁺ ions from NaCl = 0.24 mol

total number of Na⁺ ions in the mixture = 0.16 mol + 0.24 mol = 0.4 mol
as stated the volumes are additive, 
therefore total volume  = 100 ml + 200 ml = 300 ml 
the concentration of Na⁺ ions = number of moles / volume 
                                              = 0.4 mol/ 0.3 dm³
concentration of Na⁺ = 1.33 mol/dm³
5 0
3 years ago
Tell me answer........... fast ​
blondinia [14]
The answer will be 34
Hope you get it

7 0
3 years ago
Read 2 more answers
How many moles are in 5.67x10^24 atoms of RbCl?
Mademuasel [1]

Answer:

<h2>9.42 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{5.67 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 9.418604...

We have the final answer as

<h3>9.42 moles</h3>

Hope this helps you

4 0
3 years ago
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