Where speed is distance/time, velocity is displacement/time.
What this means is that velocity is the length covered in relation to the starting point.
Speed is just the distance travelled no matter where you began.
When going around a circular track, you might have a speed value. However, since you get back to the same location at every lap, you have 0 velocity.
Hope I helped :)
Explanation:
The magnitude of the electric field between the plates is given by
E = -ΔV/d
minus sign indicates Potential decreases in the direction of electric field
where
ΔV is the potential difference between the plates
D is the distance between the plates.
The work done when carrying an electrical charge on an equipotential surface between one position to the other is zero W= q(V-V)=0 The electric field lines of force are always perpendicular to an equipotential surface. That conductor in an equipotential surface as direction E is at right angles to an eauipotential surface The intensity of the electric field along an equipotential surface is always zero. Equipotential surfaces never collide with each other as this would mean that at that point, there are two alternative values that are not true.
Answer:
The acceleration of the mass is 2 meters per square second.
Explanation:
By Newton's second law, we know that force (
), measured in newtons, is the product of mass (
), measured in kilograms, and net acceleration (
), measured in meters per square second. That is:
(1)
The initial force applied in the mass is:


In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to
of the initial force. The acceleration of the mass is:


The acceleration of the mass is 2 meters per square second.
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Answer:
5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity
Explanation:
The concept to solve this problem is given by Energy Transferred, the equation is given by,

Where,
Q= Energy transferred
m = mass of water
c = specific heat capacity
Temperature change (K or °C)
Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,



Then we can calculate the heat absorbed by m grams of ice at 0°C, then

How Q_1=Q_2, so



Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity