Answer:
1) Hydrolysis
2)Dehydration
3)Dehydration
4)Hydrolysis
Explanation:
Hydrolysis is the chemical breakdown of substances by water and depends on the chemistry, solubility, pH, and the oxidation–reduction (Eh or redox) potential of compound
<em>https://www.sciencedirect.com/topics/earth-and-planetary-sciences/hydrolysis</em>
With hydrolysis water will be a reactant, not a product, and is associated with breaking down substances. Hence 1 and 4 being a Hydrolysis reaction.
Dehydration on the other hand, is defined as :
In a dehydration reaction, either a hydroxyl group from one molecule combines with a hydrogen atom from the other molecule, or two hydrogen atoms from one molecule combine with an oxygen atom on the other molecule. In either case, water is released, and the two molecules are joined together.
https://www.albert.io/blog/dehydration-synthesis-ap-biology-crash-course/
Therefore it is associated with creating a bond of sorts, and water is a product, which is why 2 and 3 are dehydration.
Hope this helps!
<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
<u>Explanation:</u>
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
The equation given by Henry's law is:
......(1)
where,
= solubility of carbon dioxide in water = 0.161 g/100 mL
= Henry's constant = ?
= partial pressure of carbon dioxide = 760 mmHg
Putting values in equation 1, we get:

Now, calculating the pressure of carbon dioxide using equation 1, we get:
= solubility of carbon dioxide in water = 0.886 g/100 mL
= Henry's constant = 4720.5 g.mmHg/100 mL
= partial pressure of carbon dioxide = ?
Putting values in equation 1, we get:

Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg
Answer:
The molarity (M) of the following solutions are :
A. M = 0.88 M
B. M = 0.76 M
Explanation:
A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.
Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)
= 27 + 3(16 + 1)
= 27 + 3(17) = 27 + 51
= 78 g/mole
= 78 g/mole
Given mass= 19.2 g/mole


Moles = 0.246

Volume = 280 mL = 0.280 L

Molarity = 0.879 M
Molarity = 0.88 M
B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr
Molar mass of KBr = 119 g/mole
Given mass = 235.9 g

Moles = 1.98
Volume = 2.6 L


Molarity = 0.762 M
Molarity = 0.76 M
Answer:
It is always twice the value of the actual yield.
Explanation: