Answer:
[NH₃] = 14.7 mol/L
Explanation:
28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.
Let's determine the amount of ammonia:
28 g . 1 mol / 17.03g = 1.64 moles of NH₃
You need to consider that, when you have density's data it is always referred to solution:
Mass of solution is 100 g, let's find out the volume
0.90 g/mL = 100 g /V
V = 100 g / 0.90mL/g → 111.1 mL
We convert the volume to L → 111.1 mL . 1 L/1000mL = 0.1111 L
mol/L = 1.64 mol/0.1111L → 14.7 M
mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution
Answer:
I can't answer this as I am not able to read the Question
Answer: The answer is D. This has a Carboxylic Acid group, and is acetic acid, or Ethanoic Acid.
ALWAYS LOOK for the Functional Group in question.
A. Would likely not stay in water, or at least not be acidic, for it is butane gas.
B. Is 1-propanol, and alcohols are not acidic as a rule. Certainly not in water.
C. This is an Ether. It will not give up an H+, it it not an acid.
E. This functional group is an amine, which is more “base” like, since the lone pairs of the Nitrogen atom would tend to attract a H+.
Answer:
I Think it might be A! I hope I am right!
