Question

HURRY WILL GIVE BRAINLIESTHow much heat is needed to melt 45.00 g of ice at 0°C if the latent heat of fusion of water is 333.7 J/g?
a. 288.7 Jb. 378.7 Jc. 14,220 Jd. 15,020 J

Answer 1

D. 15,020 J

heat = 45 x 333.7 j = 15016.5j

Answer 2

Answer:

d. 15,020 J

Explanation:

As we know that heat required to change the phase of of ice is given as

$Q = mL$

here we we know that

m = 45.00 gm

also we know that

Latent heat is L = 333.7 J/g

Now from above formula

$Q = 45 \times 333.7$

$Q = 15020 J$

so correct answer will be

d. 15,020 J