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3 years ago

15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the

Physics

1 answer:

goldfiish [28.3K]3 years ago

5 0

The final combined velocity after the collision is 20.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two car and of the truck must be conserved before and after the collision.

This means that we can write the following equation:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 800 kg$ is the mass of the sport car

$u_1 = 13.0 m/s$ is the initial velocity of the car (taking its direction as positive direction)

$m_2 = 1200 kg$ is the mass of the truck

$u_2 = 25.0 m/s$ is the initial velocity of the truck

$v$ is the final combined velocity of the car and the truck, after the collision

Re-arranging the equation and substituting the values, we find the velocity after the collision:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(800)(13)+(1200)(25)}{800+1200}=20.2 m/s$

And the positive sign indicates their final direction is the same as the initial direction of the two vehicles.

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A toy rocket, mass 0.8 kg, blasts up at a 45 degrees from ground level with a kinetic energy of 41 J. To what maximum vertical h

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Answer:

The maximum height reached by the toy rocket is 0.73 meters.

Explanation:

It is given that,

Mass of the toy rocket, m = 0.8 kg

It is projected at an angle of 45 degrees from ground level. The kinetic energy of the rocket is used to find the velocity with which it was projected as :

$K=\dfrac{1}{2}mv^2$

$v=\sqrt{\dfrac{2K}{m}}$

$v=\sqrt{\dfrac{2\times 41}{0.8}}$

u = 10.12 m/s

When it reaches to a maximum height, its final velocity will be equal to 0, v = 0

Using third equation of motion to find it as :

$v^2-u^2=2as$

a = -g

$-u^2=-2gs$

s is the maximum height reached by the toy rocket

In vertical direction, $u_y=u\ sin\theta$

$s=\dfrac{u_y}{2g}$

$s=\dfrac{u\ sin\theta}{2g}$

$s=\dfrac{10.12\times sin(45)}{2\times 9.8}$

s = 0.36 meters

So, the maximum height reached by the toy rocket is 0.73 meters. Hence, this is the required solution.

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