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olga_2 [115]
3 years ago
15

A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?

Chemistry
1 answer:
sattari [20]3 years ago
6 0

V2 = 276 ml

Explanation:

Given:

V1 = 250 ml V2 = ?

T1 = 293K. T2 = 324K

Here, we use Charles's law:

V1/T1 = V2/T2

Solving for P2, we get

V2 = (T2/T1)V1

= (324K/293K)(250 ml)

= 276 ml

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Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

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T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

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The density of lead is 11.4g/cm3. What volume, in ft3, would be occupied by 10.0 g of lead?
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Answer:

3.10×10¯⁵ ft³.

Explanation:

The following data were obtained from the question:

Density (D) of lead = 11.4 g/cm³

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Density (D) = mass (m) / Volume (V)

D = m/V

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