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3 years ago

How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?

Chemistry

1 answer:

EastWind [94]3 years ago

8 0

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

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Answer:

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General Formulas and Concepts:

Atomic Structure

Moles
Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume (in L)
n is number of moles
R is gas constant
T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

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Step 2: Solve for V

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