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strojnjashka [21]
3 years ago
6

Because the light rays never meet, a concave lens can produce

Chemistry
1 answer:
Arturiano [62]3 years ago
4 0

Answer:

Virtual images.

Hope this helps.

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6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at
sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K

Now put all the given values in above equation, we get:

\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

6 0
2 years ago
Helppppppppppp please
valentinak56 [21]
Your answer would have to be #3
4 0
3 years ago
♔♔Can water stay liquid below zero degrees Celsius?✞♡♡♡​
astra-53 [7]

Answer:

Yes, water can stay liquid below zero degrees Celsius. There are a few ways in which this can happen. The freezing point of water drops below zero degrees Celsius as you apply pressure. When we apply pressure to a liquid, we force the molecules to get closer together.

Explanation:

Hope this helps you. Have a nice day.^_^

Please mark as brainliest. It helps a lot:)

6 0
3 years ago
Read 2 more answers
A balloon has a volume of 3.0 L at room temperature (27oC). At what temperature would the balloon have a volume of 4.0L?
diamong [38]

Answer: 400K

Explanation:

Given that,

Original volume of balloon V1 = 3.0L

Original temperature of balloonT1 = 27°C

Convert the temperature in Celsius to Kelvin

(27°C + 273 = 300K)

New volume of balloon V2 = 4.0L

New temperature of balloon T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

3.0L/300K = 4.0L/T2

To get the value of T2, cross multiply

3.0L x T2 = 4.0L x 300K

3.0LT2 = 1200LK

Divide both sides by 3.0L

3.0LT2/3.0L = 1200LK/3.0L

T2 = 400K

Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.

6 0
3 years ago
Toluene, c6h5ch3, is a liquid compound similar to benzene, c6h6. it is the starting material for other substances, including tri
babymother [125]
Toulene = 35.6 g 
Benzene = 125 g = 0.125 kg
 Molecular weight of Toluene C6H5CH3 = 92.1g/mol
 Moles of toulene = 35.6 g / 92.1 g/mol = 0.3865 mol

 Now the molarity of the toulene in the given solution = 0.3865 / 0.125 = 3.092 m 
 Molarity of C6H5CH3 = 3.092 m
6 0
3 years ago
Read 2 more answers
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