Answer:
Evaporation is the method of separating a solid (solute) from a homogeneous solution.
in this method, the solution is heated until the solvent gets evaporated in the form of vapor and the solute is left behind as residue.
Answer:
(a)

(b)

Explanation:
Hello,
(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:
![\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3Dkt%20%2B%5Cfrac%7B1%7D%7B%5BNOBr%5D_0%7D%5C%5C%5Cfrac%7B1%7D%7B%5BNOBr%5D%7D%3D%5Cfrac%7B0.8%7D%7BM%2As%7D%2A22s%2B%5Cfrac%7B1%7D%7B0.086M%7D%3D%5Cfrac%7B29.3%7D%7BM%7D%5C%5C)
![[NOBr]=\frac{1}{29.2/M}=0.0342M](https://tex.z-dn.net/?f=%5BNOBr%5D%3D%5Cfrac%7B1%7D%7B29.2%2FM%7D%3D0.0342M)
(b) Now, for a second-order reaction, the half-life is computed as shown below:
![t_{1/2}=\frac{1}{k[NOBr]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BNOBr%5D_0%7D)
Therefore, for the given initial concentrations one obtains:

Best regards.
Answer:
The answer for 2-hexene is that the structure should have 6 carbon with a double bond beginning on the 2nd carbon atom.
The answer for 1-pentyne is that the structure should have 5 carbon with triple bond beginning on the 1st carbon atom.
Explanation:
<u>2-Hexene</u>
The structural formula for 2-hexene will have 6 carbons because the nomenclature has a -hex prefix, which stands for 6 carbons.
The -ene suffix of the nomenclature means that the organic compound is an alkene. Alkenes are hydrocarbons that contain double covalent bond and have the suffix -ene.
The double bond is on the 2 carbon atom because the nomenclature states that the double bond will be on the 2 carbon atom.
<u>1-Pentyne</u>
The structure will have 5 carbons since the -pent prefix means 5 carbons.
The structure has a triple bond because the -yne suffix means that the structure is an alkyne. An alkyne is a hydrocarbon with triple covalent bonds.
Also, the position of the triple bond is known because the nomenclature of the alkyne states that the triple bond is on the 1st carbon.
A is the reasonable answer
Answer:
V₂ = 457.49 mL
Explanation:
Given that,
Initial volume, 
Initial temperature, 
Final temperature, 
We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :

Put the respected values,

So, the final volume of the gas is equal to 457.49 mL.