The answer is <span>ionic aluminum fluoride (</span>AlF3). Note that boiling points of pure solvents are raised in the presence of solutes. The type of solute also affects the boiling point elevation of the solution. Ionic substances tend to raise it more than covalent ones, so sucrose is out of the picture. Next, consider the number of ions the ionic substance produces. The more ions, the greater the BPE. AlF3 dissociates into 4 ions.
Answer:
a.
b.
Explanation:
a. First, we solve the specific heat equation as follows:
b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:
Answer:
<span>Chlorine (Cl) is the oxidizing agent because it gains an electron.
Explanation:
Reaction is as follow,
</span><span> Cl</span>₂<span> (aq) + 2 Br</span>⁻<span> (aq) </span>→ <span> 2Cl(aq) + Br</span>₂ <span>(aq)
Oxidation Reaction:
2 Br</span>⁻ → Br₂ + 2 e⁻
Two atoms of Br⁻ (Bromide) looses two electrons to form Br₂ molecule. Hence it is oxidized and is acting as reducing agent.
Reduction Reaction:
Cl₂ + 2 e⁻ → 2 Cl⁻
One molecule of Cl₂ gains two electrons to form two chloride ions (Cl⁻). Therefore, it is reduced and has oxidized Br⁻, Hence, acting as a oxidizing agent.
<span>According to the question-
1 mol C3H8O = 60.096 g C3H8O
2 mol C3H8O = 9 mol O2
1 mol O2 = 31.998 g O2
[(3.00 g C3H8O)/1][(1 mol C3H8O)/(60.096)][(9 mol O2)/(2 mol C3H8O)][(32.998 g O2)/(1 mol O2)] = 7.1880435 g O2
Since 7.1880435 g of O2 is needed, and 7.38 g of O2 is available, 0.199565 g of O2 will be left over and oxygen is present in excess.
Next, we need to convert 0.199565 g of O2 into moles of O2:
[(0.199565 g O2)/1][(1 mol O2)/(31.998 g O2)] = 0.005999 mol O2, or 0.006 mol O2</span>
