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3 years ago

a piece of wood weighing 10 ounces is found to have a weight of 8 ounces after drying. the moisture content was:

1 answer:

8 0

Moisture content should be the difference of the weight of the object wet (10 oz.) and the weight of the object when it was dry(8 oz.)
So,
10 oz. - 8 oz. =moisture content, or 2 oz.

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A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,

zhuklara [117]

Answer:

$285.74\text{ inch}^2$

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of $3\text{ inch}$ . The bicycle wheel has a radius of $10\text{ inch}$ .

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel $=10\text{ inch}$

area of bicycle wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times10^2$

$=314\text{ inch}^2$

radius of bicycle training wheel $=3\text{ inch}$

area of bicycle training wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times3^2$

$=28.26\text{ inch}^2$

difference in area of bicycle wheel and bicycle training wheel

$=\text{area of bicycle wheel}-\text{area of bicycle training wheel}$

$=314-28.26$

$=285.74\text{ inch}^2$

hence the training wheel is $285.74\text{ inch}^2$ smaller than regular wheel

4 0

2 years ago

The phenomenon of bottle flipping has hit the nation. You design a machine that can randomly flip a bottle. You observe 2180 ran

krek1111 [17]

Answer:

The variable of interest is the proportion of flips that land the correct way when flipped randomly.

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

Step-by-step explanation:

Variable of Interest:

Proportion of flips that land the correct way when flipped randomly.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Necessary conditions:

The necessary conditions are:

$n\pi \geq 10$

$n(1-\pi) \geq 10$

You observe 2180 random, independent flips, and 325 land the correct way.

This means that $n = 2180, \pi = \frac{325}{2180} = 0.149$

Necessary conditions

$n\pi = 2180*0.149 = 325 \geq 10$

$n(1-\pi) = 2180*0.851 = 1855 \geq 10$

The necessary conditions $n\pi \geq 10$ and $n(1-\pi) \geq 10$ are present.

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.33$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 - 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.131$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.149 + 2.33\sqrt{\frac{0.149*0.851}{2180}} = 0.167$

The 98% confidence interval for the overall proportion of bottles that land correctly when flipped randomly is (0.131, 0.167).

8 0

3 years ago

Mario makes 6 free throw shots out of his first 10 attempts. What is the least number of consecutive shots Mario must make to in

irga5000 [103]

Answer:

4 shots

Step-by-step explanation:

3 0

2 years ago

How many liters of water will each container have if the total amount is distributed equally among the 4 containera

wel

Answer: See explanation

Step-by-step explanation:

Your question isn't complete as you didn't tell us the total amount of liters of water that we have. Let's assume that the total amount of liters of water is 50 liters a d we are told to divide it into 4 containers.

The amount of liters that each container will get will be:

= 50 liters / 4

= 12 1/2 liters each

4 0

2 years ago

Graph the line y= 2/3x +1

Dmitry [639]

Step-by-step explanation:

Given the linear equation, y = ⅔x + 1, where the <u>slope</u>, m = ⅔, and the y-intercept, (0, 1) where<em> b</em> = 1.

<h3><u>Start at the y-intercept:</u></h3>

In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis. It coordinates are (0, <em>b</em>), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.

<h3><u>Plot other points using the slope:</u></h3>

From the y-intercept, (0, 1), we must use the slope, m = ⅔ (<em>rise</em> 2, <em>run</em> 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.

Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.

3 0

2 years ago

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