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Vikentia [17]
3 years ago
6

You are given the following boiling point data. Which of the liquids would you expect to have the highest vapor pressure at room

temperature?Ethanol, C2H5OH 78.5 °CEthylene glycol, C2H4(OH)2 198.0 °CDiethyl ether, C3H10O2 34.5 °CWater, H2O 100.0 °CMethanol, CH3OH 64.96 °C
Chemistry
1 answer:
Leokris [45]3 years ago
6 0

Answer:

Diethyl ether

Explanation:

vapor pressure - the pressure exerted by the gaseous molecules on the walls of the container , is called its vapor pressure.

The compound with higher boiling point , will have lower vapor pressure ,

and the compound with lower boiling point , will have higher vapor pressure.

Hence, Boiling point and vapor pressure have inverse relation.

The vapor pressure and boiling point both, depends on the inter molecular interactions , i,e, the interaction between the molecules.  

Since, the compound with stronger inter molecular interactions, will not easily convert to gas, hence will have higher boiling point between , therefore , its vapor pressure would be less.

But the compound with less inter molecular interactions , can easily vaporize to convert to gaseous state and hence will have lower boiling point, therefore, its vapor pressure would be higher .

Among all the options , diethyl ether have lowest boiling point , hence, will have highest vapor pressure , at room temperature.

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NADPH ---------------------------------------------------------------------> NADP⁺H⁺ + 2e⁻.

Also, the balanced equation for the reduction reaction is given below as:

\frac{1}{2} O₂ + 2H⁺ + 2e⁻ --------------------------------------------------------------> H₂O.

It can be shown from the above REDOX reaction that the total number of electrons getting transferred is 2.

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The overall cell potential = E[ reduction reaction] - E[oxidation reaction] = 0.82 - (- 0.32 ) = 1.14 V.

Hence, the Gibbs energy = - 2 × 96485.3329 × 1.14 = -219.99kJ

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