Agnesium, calcium, and strontium are examples of ___________

Which statement describes the charge distribution and the polarity of a CH4 molecule?The charge distribution is symmetrical and

Alex

The charge distribution in a CH₄ molecule is symmetric.
CH₄ molecules are nonpolar.

<h3>Explanation</h3>

A CH₄ molecule has four C-H bonds. Each of the C-H bonds is weakly polar. However, the molecule has a tetrahedral shape. The shape itself is symmetric.

As a result, charges on the four C-H bonds have a symmetric distribution. They cancel out within the molecule. Overall, the molecule is nonpolar.

5 0

3 years ago

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Gold is reacted with Bromine gas according to the reaction 2Au + 3Br2 → 2AuBr3 . Use the data table below to determine the perce

Vanyuwa [196]

These link people are annoying

4 0

3 years ago

Why do you think that KCl can be used as an effective water softener and also as a drug to kill someone? What is the difference

Archy [21]

Answer: For price-sensitive customers and for customers with no sodium-related health concerns, sodium chloride is an excellent choice. It's effective, inexpensive, easily obtained and usable in any water softener. On the other hand, potassium chloride would be a better choice for other kinds of customers.

Explanation:

4 0

3 years ago

A possible mechanism for the overall reaction Br2 (g) + 2NO (g) → 2NOBr (g) is NO (g) + Br2 (g) rightwards arrow with k space 1

omeli [17]

Answer : The rate law for formation of NOBr based on this mechanism is, $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

Explanation :

The overall reaction is:

$Br_2(g)+2NO(g)\rightleftharpoons 2NOBr(g)$

Rate law = $k[Br_2][NO]^2$

The first step of the overall reaction is:

$NO(g)+Br_2(g)\overset{k_1}{\rightarrow} NOBr_2(g)$

$NO(g)+Br_2(g)\overset{k_1^-}{\leftarrow} NOBr_2(g)$

Rate law 1 = $k_1[Br_2][NO]$

Rate law 2 = $k_1^-[NOBr_2]$

The second step of the overall reaction is:

$NOBr_2(g)+NO(g)\overset{k_2}{\rightarrow} 2NOBr$

Rate law 3 = $k_2[NOBr_2][NO]$

Now rate law of overall reaction can be obtained as follows.

We are multiplying rate law 1 and rate law 3 and dividing by rate law 2, we get:

Rate law = $\frac{[k_1[Br_2][NO]]\times [k_2[NOBr_2][NO]]}{[k_1^-[NOBr_2]]}$

Rate law = $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

Rate law = $k[Br_2][NO]^2$

The rate law for formation of NOBr based on this mechanism is, $\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2$

4 0

3 years ago

Explain why thermal and electrical conductivity is so high with copper

lidiya [134]

Copper is formed of copper atoms, which are closely clustered together. If observed closely, one could witness the movement of electrons between the atoms of the copper. Each copper atom turns into a positive ion by losing one electron. Thus, copper is a lattice of positive copper ions with the movement of free electrons among them.

Due to movement of electrons freely through the metal, they are also known as conduction electrons. The presence of these conduction electrons makes the copper a good conductor of electricity and heat.

8 0

3 years ago

Agnesium, calcium, and strontium are examples of ____________.