First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl= 23 g+ 35,5 g= 58, 5 g/ mol

1 mol ------ 58, 5 g

2,5 mol---x= (2,5 mol x 58, 5 g)/ 1 mol = 146, 25 g

8 0

3 years ago

What attractive forces must be overcome when CsI is dissolvedin liquid HF?

bagirrra123 [75]

Answer:

The attractive forces must be overcome are :

Ion- ion interaction

Dipole - Dipole

Hydrogen Bonding

Explanation:

For the compound to dissolve the attractive forces existing between atoms of the compound must be reduced

CsI is ionic compound and its molecules are held together by ionic(electrostatic) force . These force must be weakened for its dissolution

Forces in HF :

1 .Hydrogen Bonding : In HF strong intermolecular Hydrogen Bonding exist between the electronegative F and Hydrogen

2. Dipole - dipole : HF is polar . So it is a permanent dipole and has dipole diople interaction

4 0

3 years ago

At what temperatures is a reaction that has a positive change in entropy

Setler [38]

Answer:

the answer is A

I made a chart for AP chem if you want to refer to it.

3 0

2 years ago