Simple dimensional analysis.
okay so youll need a periodic table to look up the molar mass. youll be given either an amount of grams or moles.
Answer:
25.2 kJ
Explanation:
The complete question is presented in the attached image to this answer.
Note that, the heat gained by the 2.00 L of water to raise its temperature from the initial value to its final value comes entirely from the combustion of the benzoic acid since there are no heat losses to the containing vessel or to the environment.
So, to obtained the heat released from the combustion of benzoic acid, we just calculate the heat required to raise the temperature of the water.
Q = mCΔT
To calculate the mass of water,
Density = (mass)/(volume)
Mass = Density × volume
Density = 1 g/mL
Volume = 2.00 L = 2000 mL
Mass = 1 × 2000 = 2000 g
C = specific heat capacity of water = 4.2 J/g.°C
ΔT = (final temperature) - (Initial temperature)
From the graph,
Final temperature of water = 25°C
Initial temperature of water = 22°C
ΔT = 25 - 22 = 3°C
Q = (2000×4.2×3) = 25,200 J = 25.2 kJ
Hope this Helps!!!
The correct answer is - b. If available resources decrease, then competition will increase.
All living organisms in an ecosystem are specialized in accordance to the living conditions and the food sources available. If a given ecosystem experiences prolonged drought, than the resources will decrease. With a decrease in resources, the living organisms will find themselves in a situation of scarcity. That will lead to a much increased competition, with both organisms of different species, and members of the same species. That will most likely lead to a situation where only the fittest will survive, while the weaker members of the species will probably die in that period of prolonged drought as they will not be able to get the resources they need to survive.
The first step is to focus on the parent carbon chain:nonane. This indicates a carbon chain with 9 carbon atoms. From here, on the 4th carbon from one side, place a Br functional group; on the 2nd carbon, place a I functional group; on the 5th and 6th carbon, place a CH₃ (methyl) functional group to each. Lastly, complete the bonding with H atoms. The structure is shown in the attached picture.
